oct()函數是Python3中的內置方法之一。 oct()方法采用整數,並以字符串格式返回其八進製表示形式。
用法: oct(x)
參數:
x-必須為整數,並且可以為二進製,十進製或十六進製格式。
返回值:值的八進製表示形式。
錯誤和異常:
TypeError:當將整數類型常量以外的任何內容作為參數傳遞時,返回TypeError。
代碼1:說明了oct()函數的用法。
# Python3 program to demonstrate
# the use of oct() function
print("The octal representation of 23 is " + oct(23))
print("The octal representation of the"
" ascii value of 'z' is " + oct(ord('z')))
# Binary representation of a number
# can be passed as parameter
# For 23, Binary is 0b10111
print("The octal representation of the binary"
" of 23 is " + oct(0b10111))
# For 23, Hexadecimal is 0x17
print("The octal representation of the binary"
" of 23 is " + oct(0x17))
輸出:
The octal representation of 23 is 0o27 The octal representation of the ascii value of 'z' is 0o172 The octal representation of the binary of 23 is 0o27 The octal representation of the binary of 23 is 0o27
代碼2:展示TypeError
# Python3 program demonstrating TypeError
print("The Octal representation of 29.5 is " + oct(29.5))
'''
# Python doesn't have anything like float.oct()
# to directly convert a floating type constant
# to it's octal representation. Conversion of a
# floating point value to it's octal is done manually.
'''
輸出:
Traceback (most recent call last): File "/home/5bf02b72de26687389763e9133669972.py", line 3, in print("The Octal representation of 29.5 is "+oct(29.5)) TypeError:'float' object cannot be interpreted as an integer
應用範圍:
oct()用於所有類型的標準轉換。例如,分別從十進製轉換為八進製,從二進製轉換為八進製,從十六進製轉換為八進製。代碼3:
# TypeConversions from decimal and binary
# to their respective octal representations
# The choices present to the user
print("a. Hexadecimal to Octal ")
print("b. Decimal to Octal")
print("c. Binary to Octal")
# Function generates octal representation
# from it's binary from
def bin_to_oct():
print("Enter your input in BIN format:-")
# taking user input as binary string and
# then using int() to convert it into it's
# respective decimal format
x = int(input(), 2)
print("Octal form of " + str(x) + " is " + oct(x) )
# Function generates octal representation
# of it's hexadecimal form passed as value.
def hex_to_oct():
print("Enter your input in HEX format:-")
# taking user input as hexadecimal string and
# then using int() to convert it into it's
# respective decimal format
x = int(input(), 16)
print("Octal form of " + str(x) + " is " + oct(x))
# Function converts decimal form to it's
# respective octal representation
def decimal_to_oct():
print("Enter a number with base-10 format:-")
# taking a simple user input and
# converting it to an integer
x = int(input())
print("Octal form of " + str(x) + " is " + oct(x))
# Driver Code
ch = input("Enter your choice:-\n")
if ch is 'a':
hex_to_oct()
elif ch is 'b':
decimal_to_oct()
elif ch is 'c':
bin_to_oct()
輸出:
a. Hexadecimal to Octal b. Decimal to Octal c. Binary to Octal Enter your choice:- a Enter your input in HEX format:- 0x13 Octal form of 19 is 0o23
a. Hexadecimal to Octal b. Decimal to Octal c. Binary to Octal Enter your choice:- b Enter a number with base-10 format:- 123 Octal form of 123 is 0o173
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