MySQL ORDER BY用法及代碼示例

MySQL 的 ORDER BY 子句對檢索到的記錄進行排序，並默認按升序返回它們。如果需要的話，我們可以指定按降序排序。

用法

SELECT column_name(s)
FROM table_name
ORDER BY column1, column2 (DESC);

例子

考慮下表有關一些學生的信息：

student_id	名稱	名字	day_enrolled	年齡	用戶名
1	Sky	Towner	2015-12-03	17	stowner1
2	Ben	Davis	2016-04-20	19	bdavis2
3	Travis	Apple	2018-08-14	18	tapple3
4	Arthur	David	2016-04-01	16	adavid4
5	Benjamin	Town	2014-01-01	17	btown5

可以使用此處的代碼創建上述示例表。

升序

要按 age 升序對學生進行排序：

SELECT * FROM students
ORDER BY age;



+------------+----------+--------+--------------+------+----------+
| student_id | fname    | lname  | day_enrolled | age  | username |
+------------+----------+--------+--------------+------+----------+
|          4 | Arthur   | David  | 2016-04-01   |   16 | adavid4  |
|          1 | Sky      | Towner | 2015-12-03   |   17 | stowner1 |
|          5 | Benjamin | Town   | 2014-01-01   |   17 | btown5   |
|          3 | Travis   | Apple  | 2018-08-14   |   18 | tapple3  |
|          2 | Ben      | Davis  | 2016-04-20   |   19 | bdavis2  |
+------------+----------+--------+--------------+------+----------+

降序

要按 age 降序對學生進行排序：

SELECT * FROM students
ORDER BY age DESC;



+------------+----------+--------+--------------+------+----------+
| student_id | fname    | lname  | day_enrolled | age  | username |
+------------+----------+--------+--------------+------+----------+
|          2 | Ben      | Davis  | 2016-04-20   |   19 | bdavis2  |
|          3 | Travis   | Apple  | 2018-08-14   |   18 | tapple3  |
|          1 | Sky      | Towner | 2015-12-03   |   17 | stowner1 |
|          5 | Benjamin | Town   | 2014-01-01   |   17 | btown5   |
|          4 | Arthur   | David  | 2016-04-01   |   16 | adavid4  |
+------------+----------+--------+--------------+------+----------+

按字母順序

根據學生名字的字母順序對學生進行排序：

SELECT * FROM students
WHERE fname is NOT NULL
ORDER BY fname;



+------------+----------+--------+--------------+------+----------+
| student_id | fname    | lname  | day_enrolled | age  | username |
+------------+----------+--------+--------------+------+----------+
|          4 | Arthur   | David  | 2016-04-01   |   16 | adavid4  |
|          2 | Ben      | Davis  | 2016-04-20   |   19 | bdavis2  |
|          5 | Benjamin | Town   | 2014-01-01   |   17 | btown5   |
|          1 | Sky      | Towner | 2015-12-03   |   17 | stowner1 |
|          3 | Travis   | Apple  | 2018-08-14   |   18 | tapple3  |
+------------+----------+--------+--------------+------+----------+

對多列進行排序

對於具有相同 age 的學生，按照 age 的升序排列學生，然後按照 fname 的降序排列：

SELECT * 
FROM students
WHERE fname is NOT NULL
ORDER BY age, fname DESC;



+------------+----------+--------+--------------+------+----------+
| student_id | fname    | lname  | day_enrolled | age  | username |
+------------+----------+--------+--------------+------+----------+
|          4 | Arthur   | David  | 2016-04-01   |   16 | adavid4  |
|          1 | Sky      | Towner | 2015-12-03   |   17 | stowner1 |
|          5 | Benjamin | Town   | 2014-01-01   |   17 | btown5   |
|          3 | Travis   | Apple  | 2018-08-14   |   18 | tapple3  |
|          2 | Ben      | Davis  | 2016-04-20   |   19 | bdavis2  |
+------------+----------+--------+--------------+------+----------+

當列條目具有重複數據時，對多列進行排序是有意義的(在這種情況下 'Sky' 和 'Benjamin' 都是 17 )。對於 'Sky' 和 'Benjamin'，我們然後根據 fname 的字母降序順序確定它們的順序，這就是為什麽 'Sky' 在 'Benjamin' 之上返回。

相關用法

注：本文由純淨天空篩選整理自Arthur Yanagisawa大神的英文原創作品 MySQL | ORDER BY。非經特殊聲明，原始代碼版權歸原作者所有，本譯文未經允許或授權，請勿轉載或複製。