當前位置: 首頁>>代碼示例 >>用法及示例精選 >>正文


Python numpy.ptp()用法及代碼示例


numpy.ptp()函數用於通過找出給定數字的範圍在統計中發揮重要作用。範圍=最大值-最小值。

用法:ndarray.ptp(axis=None, out=None)
參數:
arr :input array.
axis:axis along which we want the range value. Otherwise, it will consider arr to be flattened(works on all the axis). axis = 0 means along the column and axis = 1 means working along the row.
out : [ndarray, optional]Different array in which we want to place the result. The array must have same dimensions as expected output.

返回:數組的範圍(如果軸為空則為標量值)或數組的值沿指定軸的範圍。


代碼1:工作

# Python Program illustrating  
# numpy.ptp() method  
    
import numpy as np 
    
# 1D array  
arr = [1, 2, 7, 20, np.nan] 
print("arr:", arr)  
print("Range of arr:", np.ptp(arr)) 
  
 1D array  
arr = [1, 2, 7, 10, 16] 
print("arr:", arr)  
print("Range of arr:", np.ptp(arr))

輸出:

arr: [1, 2, 7, 20, nan]
Range of arr: nan
arr: [1, 2, 7, 10, 16]
Range of arr: 15


代碼2:

# Python Program illustrating  
# numpy.ptp() method  
  
import numpy as np 
  
# 3D array  
arr = [[14, 17, 12, 33, 44],   
       [15, 6, 27, 8, 19],  
       [23, 2, 54, 1, 4,]]  
print("\narr:\n", arr)  
     
# Range of the flattened array  
print("\nRange of arr, axis = None:", np.ptp(arr))  
     
# Range along the first axis  
# axis 0 means vertical  
print("Range of arr, axis = 0:", np.ptp(arr, axis = 0))  
     
# Range along the second axis  
# axis 1 means horizontal  
print("Min of arr, axis = 1:", np.ptp(arr, axis = 1))  

輸出:

arr:
 [[14, 17, 12, 33, 44], [15, 6, 27, 8, 19], [23, 2, 54, 1, 4]]

Range of arr, axis = None: 53
Range of arr, axis = 0: [ 9 15 42 32 40]
Min of arr, axis = 1: [32 21 53]


代碼3:

# Python Program illustrating  
# numpy.ptp() method  
  
import numpy as np 
  
arr1 = np.arange(5)  
print("\nInitial arr1:", arr1) 
   
# using out parameter 
np.ptp(arr, axis = 0, out = arr1) 
   
print("Changed arr1(having results):", arr1)

輸出:

Initial arr1: [0 1 2 3 4]
Changed arr1(having results): [ 9 15 42 32 40]



相關用法


注:本文由純淨天空篩選整理自Mohit Gupta_OMG 大神的英文原創作品 numpy.ptp() in Python。非經特殊聲明,原始代碼版權歸原作者所有,本譯文未經允許或授權,請勿轉載或複製。