Java java.util.regex.Matcher.find()用法及代碼示例

描述

這個java.time.Matcher.find()方法嘗試找到與模式匹配的輸入序列的下一個子序列。

聲明

以下是聲明java.time.Matcher.find()方法。

public boolean find()

返回值

當且僅當輸入序列的子序列與此匹配器的模式匹配時才為真。

示例

下麵的例子展示了 java.time.Matcher.find() 方法的用法。

package com.tutorialspoint;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class MatcherDemo {
   private static String REGEX = "(a*b)(foo)";
   private static String INPUT = "aabfooaabfooabfoob";
   private static String REPLACE = "-";
   
   public static void main(String[] args) {
      Pattern pattern = Pattern.compile(REGEX);
      
      // get a matcher object
      Matcher matcher = pattern.matcher(INPUT);
      
      while(matcher.find()) {
         //Prints the offset after the last character matched.
         System.out.println("First Capturing Group, (a*b) Match String end():"+matcher.end());    
         System.out.println("Second Capturing Group, (foo) Match String end():"+matcher.end(1));  
      }
   }
}

讓我們編譯並運行上麵的程序，這將產生以下結果——

First Capturing Group, (a*b) Match String end():6
Second Capturing Group, (foo) Match String end():3
First Capturing Group, (a*b) Match String end():12
Second Capturing Group, (foo) Match String end():9
First Capturing Group, (a*b) Match String end():17
Second Capturing Group, (foo) Match String end():14