Guava庫中Doubles類的concat()方法用於將許多數組的值連接到一個數組中。這些要串聯的雙精度數組被指定為此方法的參數。
For example: concat(new double[] {a, b}, new double[] {}, new double[] {c}
returns the array {a, b, c}.
用法:
public static double[] concat(double[]... arrays)
參數:此方法接受數組作為參數,該數組是此方法要連接的雙精度數組。
返回值:此方法返回單個double數組,該數組按其原始順序包含所有指定的double數組值。
以下示例程序旨在說明concat()方法的使用:
範例1:
// Java code to show implementation of
// Guava's Doubles.concat() method
import com.google.common.primitives.Doubles;
import java.util.Arrays;
class GFG {
// Driver's code
public static void main(String[] args)
{
// Creating 2 Double arrays
double[] arr1 = { 1.2, 2.3, 3.5, 4.4, 5.1 };
double[] arr2 = { 6.2, 2.1, 7.2, 0.4, 8.7 };
// Using Doubles.concat() method to combine
// elements from both arrays into a single array
double[] res = Doubles.concat(arr1, arr2);
// Displaying the single combined array
System.out.println(Arrays.toString(res));
}
}
輸出:
[1.2, 2.3, 3.5, 4.4, 5.1, 6.2, 2.1, 7.2, 0.4, 8.7]
範例2:
// Java code to show implementation of
// Guava's Doubles.concat() method
import com.google.common.primitives.Doubles;
import java.util.Arrays;
class GFG {
// Driver's code
public static void main(String[] args)
{
// Creating 4 Double arrays
double[] arr1 = { 1.2, 2.3, 3.4 };
double[] arr2 = { 4.5, 5.6 };
double[] arr3 = { 6.4, 7.6, 8.7 };
double[] arr4 = { 9.7, 0.8 };
// Using Doubles.concat() method to combine
// elements from both arrays into a single array
double[] res
= Doubles.concat(arr1, arr2, arr3, arr4);
// Displaying the single combined array
System.out.println(Arrays.toString(res));
}
}
輸出:
[1.2, 2.3, 3.4, 4.5, 5.6, 6.4, 7.6, 8.7, 9.7, 0.8]
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注:本文由純淨天空篩選整理自Sahil_Bansall大神的英文原創作品 Java Guava | Doubles.concat() method with Examples。非經特殊聲明,原始代碼版權歸原作者所有,本譯文未經允許或授權,請勿轉載或複製。