Java IsoChronology isLeapYear()用法及代碼示例

java.time.chrono.IsoChronology類的isLeapYear()方法用於區分a年和非ap年。如果是a年，則將返回true，否則返回false。

用法:

public boolean isLeapYear(long prolepticYear)

參數：此方法將prolepticYear作為參數來檢查是否為is年。

返回值：如果有效年份為leap年，則此方法返回布爾值true，否則返回false。

下麵是說明isLeapYear()方法的示例：

範例1：

// Java program to demonstrate 
// isLeapYear() method 
  
import java.util.*; 
import java.io.*; 
import java.time.*; 
import java.time.chrono.*; 
  
public class GFG { 
    public static void main(String[] argv) 
    { 
        // creating and initializing LocalDate Object 
        LocalDate hidate = LocalDate.now(); 
  
        // getting IsoChronology used in LocalDate 
        IsoChronology crono = hidate.getChronology(); 
  
        // getting id of this Chronology 
        // by using isLeapYear() method 
        boolean flag = crono.isLeapYear(1444); 
  
        // display the result 
        if (flag) 
            System.out.println("this is leap year"); 
        else
            System.out.println("this is non leap year"); 
    } 
}

輸出：

this is leap year

範例2：

// Java program to demonstrate 
// isLeapYear() method 
  
import java.util.*; 
import java.io.*; 
import java.time.*; 
import java.time.chrono.*; 
  
public class GFG { 
    public static void main(String[] argv) 
    { 
        // creating and initializing LocalDate Object 
        LocalDate hidate = LocalDate.now(); 
  
        // getting IsoChronology used in LocalDate 
        IsoChronology crono = hidate.getChronology(); 
  
        // getting id of this Chronology 
        // by using isLeapYear() method 
        boolean flag = crono.isLeapYear(2005); 
  
        // display the result 
        if (flag) 
            System.out.println("this is leap year"); 
        else
            System.out.println("this is non leap year"); 
    } 
}

輸出：

this is non leap year

參考： https://docs.oracle.com/javase/9/docs/api/java/time/chrono/IsoChronology.html#isLeapYear-long-

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注：本文由純淨天空篩選整理自RohitPrasad3大神的英文原創作品 IsoChronology isLeapYear() method in Java with Example。非經特殊聲明，原始代碼版權歸原作者所有，本譯文未經允許或授權，請勿轉載或複製。