Elixir URI.new!用法及代碼示例

@spec new!(t() | String.t()) :: t()

與 new/0 類似，但如果給出了無效字符串，則會引發 URI.Error 。

例子

iex> URI.new!("https://elixir-lang.org/")
%URI{
  fragment: nil,
  host: "elixir-lang.org",
  path: "/",
  port: 443,
  query: nil,
  scheme: "https",
  userinfo: nil
}

iex> URI.new!("/invalid_greater_than_in_path/>")
** (URI.Error) cannot parse due to reason invalid_uri: ">"

給出一個現有的 URI 隻是簡單地返回它：

iex> uri = URI.new!("https://elixir-lang.org/")
iex> URI.new!(uri)
%URI{
  fragment: nil,
  host: "elixir-lang.org",
  path: "/",
  port: 443,
  query: nil,
  scheme: "https",
  userinfo: nil
}