Elixir NaiveDateTime.diff用法及代碼示例

@spec diff(Calendar.naive_datetime(), Calendar.naive_datetime(), System.time_unit()) ::
  integer()

從 naive_datetime1 中減去 naive_datetime2 。

答案可以在 System.time_unit/0 提供的任何 unit 中返回。

此函數返回根據 Calendar.ISO 測量秒數的秒數差異。

例子

iex> NaiveDateTime.diff(~N[2014-10-02 00:29:12], ~N[2014-10-02 00:29:10])
2
iex> NaiveDateTime.diff(~N[2014-10-02 00:29:12], ~N[2014-10-02 00:29:10], :microsecond)
2_000_000
iex> NaiveDateTime.diff(~N[2014-10-02 00:29:10.042], ~N[2014-10-02 00:29:10.021], :millisecond)
21
iex> NaiveDateTime.diff(~N[2014-10-02 00:29:10], ~N[2014-10-02 00:29:12])
-2
iex> NaiveDateTime.diff(~N[-0001-10-02 00:29:10], ~N[-0001-10-02 00:29:12])
-2

# to Gregorian seconds
iex> NaiveDateTime.diff(~N[2014-10-02 00:29:10], ~N[0000-01-01 00:00:00])
63579428950