Java BigInteger signum()用法及代碼示例

先決條件：BigInteger基礎
java.math.BigInteger.signum()方法可幫助我們識別BigInteger是正數還是零數或負數。根據以下條件，它將返回以下值之一：

當數字為負數時返回-1
當數字為零時返回0
當數字為正時返回+1

用法:

public int signum()

參數：該方法不帶任何參數。

返回值：當它們分別為負數，零或正數時，此方法返回-1、0或1作為此BigInteger的值。

例子：

Input: 2300 
Output: 1
Explanation: 2300 is postive number 
so the method returns 1

Input: -5482549 
Output: -1

以下示例程序旨在說明BigInteger的signum()方法。

// Program Demonstrate signum() method of BigInteger  
  
import java.math.*; 
  
public class GFG { 
  
    public static void main(String[] args) 
    { 
        // Creating BigInteger object 
        BigInteger biginteger = new BigInteger("2300"); 
  
        // Call signum() method on bigInteger 
        // store the return value as int 
        int sigvalue = biginteger.signum(); 
  
        // Depending upon sign value find sign of biginteger 
        String sign = null; 
        if (sigvalue == 0) 
            sign = "zero"; 
        else if (sigvalue == 1) 
            sign = "positive"; 
        else
            sign = "negative"; 
  
        // Defining result 
        String result = "BigInteger " + biginteger + " is " +  
        sign + " and Sing value is " + sigvalue; 
  
        // Print result 
        System.out.println(result); 
    } 
}

輸出：

BigInteger 2300 is positive and Sing value is 1

參考：https://docs.oracle.com/javase/7/docs/api/java/math/BigInteger.html#signum()

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注：本文由純淨天空篩選整理自AmanSingh2210大神的英文原創作品 BigInteger signum() Method in Java。非經特殊聲明，原始代碼版權歸原作者所有，本譯文未經允許或授權，請勿轉載或複製。