Java BigInteger flipBit()用法及代碼示例

先決條件：BigInteger基礎
的java.math.BigInteger.flipBit(index)方法返回一個BigInteger，該值用於翻轉BigInteger中的特定位位置。此方法計算(bigInteger ^(1

用法:

public BigInteger flipBit(int index)

參數：該方法接受一個整數類型的參數索引，表示要翻轉的位的位置。

返回值：該方法在位置索引處翻轉bigInteger後返回其值。

拋出：當index的值為負時，該方法拋出ArithmeticException。

例子：

Input: value = 2300 , index = 1
Output: 2302
Explanation:
Binary Representaion of 2300 = 100011111100
bit at index 1 is 0 so flip the bit at index 1 and it becomes 1. 
Now Binary Representation becomes 100011111110
and Decimal equivalent of 100011111110 is 2302

Input: value = 5482549 , index = 5
Output: 5482517

以下示例程序旨在說明BigInteger的flipBit(index)方法。

/* 
*Program Demonstrate flipBit() method of BigInteger  
*/
import java.math.*; 
  
public class GFG { 
  
    public static void main(String[] args) 
    { 
        // Creating  BigInteger object 
        BigInteger biginteger = new BigInteger("5482549"); 
  
        // Creating an int i for index 
        int i = 5; 
  
        // Call flipBit() method on bigInteger at index i 
        // store the return BigInteger 
        BigInteger changedvalue = biginteger.flipBit(i); 
  
        String result = "After applying flipBit at index " + i + 
        " of " + biginteger+ " New Value is " + changedvalue; 
  
        // Print result 
        System.out.println(result); 
    } 
}

輸出：

After applying flipBit at index 5 of 5482549 New Value is 5482517

參考：https://docs.oracle.com/javase/7/docs/api/java/math/BigInteger.html#clearBit(int)

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注：本文由純淨天空篩選整理自AmanSingh2210大神的英文原創作品 BigInteger flipBit() Method in Java。非經特殊聲明，原始代碼版權歸原作者所有，本譯文未經允許或授權，請勿轉載或複製。