Java AbstractList iterator()用法及代碼示例

java.util.AbstractList 類的 iterator() 方法用於以合適的順序返回此列表中元素的迭代器。

此實現返回迭代器接口的簡單實現，依賴於後備列表的 size()、get(int) 和 remove(int) 方法。

用法:

public Iterator iterator()

返回值：此方法以合適的順序返回此列表中元素的迭代器。

以下是說明 iterator() 方法的示例。

範例1：


// Java program to demonstrate
// iterator() method
// for Integer value
  
import java.util.*;
  
public class GFG1 {
    public static void main(String[] argv)
        throws Exception
    {
  
        try {
  
            // Creating object of AbstractList<Integer>
            AbstractList<Integer>
                arrlist1 = new ArrayList<Integer>();
  
            // Populating arrlist1
            arrlist1.add(10);
            arrlist1.add(20);
            arrlist1.add(30);
            arrlist1.add(40);
            arrlist1.add(50);
  
            // print arrlist1
            System.out.println("ArrayList:"
                               + arrlist1);
  
            // creating object of Iterator
            // using iterator() method
            Iterator it = arrlist1.iterator();
  
            // printing the iterated value
            while (it.hasNext()) {
                System.out.println("Value is:"
                                   + it.next());
            }
        }
  
        catch (NullPointerException e) {
            System.out.println("Exception thrown:" + e);
        }
    }
}

輸出：

ArrayList:[10, 20, 30, 40, 50]
Value is:10
Value is:20
Value is:30
Value is:40
Value is:50

範例2：


// Java program to demonstrate
// iterator() method
// for String value
  
import java.util.*;
  
public class GFG1 {
    public static void main(String[] argv)
        throws Exception
    {
  
        try {
  
            // Creating object of AbstractList<String>
            AbstractList<String>
                arrlist1 = new ArrayList<String>();
  
            // Populating arrlist1
            arrlist1.add("A");
            arrlist1.add("B");
            arrlist1.add("C");
            arrlist1.add("D");
            arrlist1.add("E");
  
            // print arrlist1
            System.out.println("ArrayList:"
                               + arrlist1);
  
            // creating object of Iterator
            // using iterator() method
            Iterator it = arrlist1.iterator();
  
            // printing the iterated value
            while (it.hasNext()) {
                System.out.println("Value is:"
                                   + it.next());
            }
        }
  
        catch (NullPointerException e) {
            System.out.println("Exception thrown:" + e);
        }
    }
}

輸出：

ArrayList:[A, B, C, D, E]
Value is:A
Value is:B
Value is:C
Value is:D
Value is:E

相關用法

注：本文由純淨天空篩選整理自RohitPrasad3大神的英文原創作品 AbstractList iterator() method in Java with Examples。非經特殊聲明，原始代碼版權歸原作者所有，本譯文未經允許或授權，請勿轉載或複製。