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Java LdapName.getPrefix方法代碼示例

本文整理匯總了Java中javax.naming.ldap.LdapName.getPrefix方法的典型用法代碼示例。如果您正苦於以下問題:Java LdapName.getPrefix方法的具體用法?Java LdapName.getPrefix怎麽用?Java LdapName.getPrefix使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在javax.naming.ldap.LdapName的用法示例。


在下文中一共展示了LdapName.getPrefix方法的4個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的Java代碼示例。

示例1: convertToRelativeName

import javax.naming.ldap.LdapName; //導入方法依賴的package包/類
public static LdapName convertToRelativeName(LdapName dn, LdapName base)
        throws NamingException {
    if (base.size() == 0) {
        return dn;
    }

    if (dn.size() < base.size()) {
        // TODO add error message
        throw new NamingException("");
    }

    Name prefix = dn.getPrefix(base.size());
    if (!prefix.equals(base)) {
        // TODO add error message
        throw new NamingException("");
    }

    return (LdapName) dn.getSuffix(base.size());

}
 
開發者ID:shannah,項目名稱:cn1,代碼行數:21,代碼來源:LdapUtils.java

示例2: testGetPrefix003

import javax.naming.ldap.LdapName; //導入方法依賴的package包/類
/**
 * <p>
 * Test method for 'javax.naming.ldap.LdapName.getPrefix(int)'
 * </p>
 * <p>
 * Here we are testing if this method correctly returns a Name that is a
 * prefix of this LdapName.
 * </p>
 * <p>
 * The expected result is an IndexOutOfBaundsException if the range is not
 * in [0,size()].
 * </p>
 */
public void testGetPrefix003() throws Exception {
    String test = "t=test";
    try {
        LdapName ln = new LdapName(test);
        ln.getPrefix(-1);
        fail("IndexOutOfBoundsException expected");
    } catch (IndexOutOfBoundsException e) {}

}
 
開發者ID:shannah,項目名稱:cn1,代碼行數:23,代碼來源:LdapNameTest.java

示例3: testGetPrefix004

import javax.naming.ldap.LdapName; //導入方法依賴的package包/類
/**
 * <p>
 * Test method for 'javax.naming.ldap.LdapName.getPrefix(int)'
 * </p>
 * <p>
 * Here we are testing if this method correctly returns a Name that is a
 * prefix of this LdapName.
 * </p>
 * <p>
 * The expected result is an IndexOutOfBaundsException if the range is not
 * in [0,size()].
 * </p>
 */
public void testGetPrefix004() throws Exception {
    String test = "t=test";
    try {
        LdapName ln = new LdapName(test);
        ln.getPrefix(2);
        fail("IndexOutOfBoundsException expected");
    } catch (IndexOutOfBoundsException e) {}
}
 
開發者ID:shannah,項目名稱:cn1,代碼行數:22,代碼來源:LdapNameTest.java

示例4: testStartsWithName004

import javax.naming.ldap.LdapName; //導入方法依賴的package包/類
/**
 * <p>
 * Test method for 'javax.naming.ldap.LdapName.startsWith(Name)'
 * </p>
 * <p>
 * Here we are testing if this method correctly returns true if an LdapName
 * starts with the given prefix.
 * </p>
 * <p>
 * The expected result is a false.
 * </p>
 */
public void testStartsWithName004() throws Exception {
    String test = "t=test,cn=test,o=other";
    LdapName ln = new LdapName(test);
    LdapName n = (LdapName) ln.getPrefix(ln.size());
    assertTrue(ln.startsWith(n));
}
 
開發者ID:shannah,項目名稱:cn1,代碼行數:19,代碼來源:LdapNameTest.java


注:本文中的javax.naming.ldap.LdapName.getPrefix方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。