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Java JdbcType.TIMESTAMP屬性代碼示例

本文整理匯總了Java中org.apache.ibatis.type.JdbcType.TIMESTAMP屬性的典型用法代碼示例。如果您正苦於以下問題：Java JdbcType.TIMESTAMP屬性的具體用法？Java JdbcType.TIMESTAMP怎麽用？Java JdbcType.TIMESTAMP使用的例子？那麽, 這裏精選的屬性代碼示例或許可以為您提供幫助。您也可以進一步了解該屬性所在類org.apache.ibatis.type.JdbcType的用法示例。


在下文中一共展示了JdbcType.TIMESTAMP屬性的11個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Java代碼示例。

示例1: select

@Select({
        "select",
        "u.id, u.name, u.email, u.creator, u.flag, u.last_login_time,c.name createUser",
        "from admin_user u LEFT JOIN admin_user c ON u.creator=c.id",
        "where u.name LIKE #{query} LIMIT #{begin},#{pagesize}"
})
@Results({
        @Result(column="id", property="id", jdbcType= JdbcType.INTEGER, id=true),
        @Result(column="name", property="name", jdbcType= JdbcType.VARCHAR),
        @Result(column="psw", property="psw", jdbcType= JdbcType.VARCHAR),
        @Result(column="email", property="email", jdbcType= JdbcType.VARCHAR),
        @Result(column="creator", property="creator", jdbcType= JdbcType.INTEGER),
        @Result(column="flag", property="flag", jdbcType= JdbcType.INTEGER),
        @Result(column="last_login_time", property="lastLoginTime", jdbcType= JdbcType.TIMESTAMP)
})
List<AdminUser> select(@Param("begin") int begin, @Param("pagesize") int pageSize, @Param("query") String query);
開發者ID:RayeWang，項目名稱:easyadmin，代碼行數:16，代碼來源:AdminUserMapper.java

示例2: selectByExample

@SelectProvider(type=MenuSqlProvider.class, method="selectByExample")
@Results({
    @Result(column="id", property="id", jdbcType= JdbcType.INTEGER, id=true),
    @Result(column="name", property="name", jdbcType= JdbcType.VARCHAR),
    @Result(column="url", property="url", jdbcType= JdbcType.VARCHAR),
    @Result(column="icon", property="icon", jdbcType= JdbcType.VARCHAR),
    @Result(column="menu_type", property="menuType", jdbcType= JdbcType.CHAR),
    @Result(column="display", property="display", jdbcType= JdbcType.INTEGER),
    @Result(column="parent_id", property="parentId", jdbcType= JdbcType.INTEGER),
    @Result(column="creator", property="creator", jdbcType= JdbcType.INTEGER),
    @Result(column="create_time", property="createTime", jdbcType= JdbcType.TIMESTAMP),
    @Result(column="update_user", property="updateUser", jdbcType= JdbcType.INTEGER),
    @Result(column="update_time", property="updateTime", jdbcType= JdbcType.TIMESTAMP),
    @Result(column="status", property="status", jdbcType= JdbcType.CHAR)
})
List<Menu> selectByExample(MenuCriteria example);
開發者ID:RayeWang，項目名稱:easyadmin，代碼行數:16，代碼來源:MenuMapper.java

示例3: selectByExample

@SelectProvider(type=RoleSqlProvider.class, method="selectByExample")
@Results({
    @Result(column="id", property="id", jdbcType= JdbcType.INTEGER, id=true),
    @Result(column="name", property="name", jdbcType= JdbcType.VARCHAR),
    @Result(column="create_time", property="createTime", jdbcType= JdbcType.TIMESTAMP),
    @Result(column="creator", property="creator", jdbcType= JdbcType.INTEGER),
    @Result(column="update_time", property="updateTime", jdbcType= JdbcType.TIMESTAMP),
    @Result(column="update_user", property="updateUser", jdbcType= JdbcType.INTEGER),
    @Result(column="description", property="description", jdbcType= JdbcType.VARCHAR)
})
List<Role> selectByExample(RoleCriteria example);
開發者ID:RayeWang，項目名稱:easyadmin，代碼行數:11，代碼來源:RoleMapper.java

示例4: select

@Select({
        "select",
        "r.id, r.name, r.create_time, r.creator,u.name as creator, r.description",
        "from role r LEFT JOIN admin_user u ON r.creator=u.id",
        "where r.name like #{query} LIMIT #{begin},#{pagesize}"
})
@Results({
        @Result(column="id", property="id", jdbcType= JdbcType.INTEGER, id=true),
        @Result(column="name", property="name", jdbcType= JdbcType.VARCHAR),
        @Result(column="create_time", property="createTime", jdbcType= JdbcType.TIMESTAMP),
        @Result(column="creator", property="creator", jdbcType= JdbcType.INTEGER),
        @Result(column="description", property="description", jdbcType= JdbcType.VARCHAR)
})
List<Role> select(@Param("begin") int begin, @Param("pagesize") int pageSize, @Param("query") String query);
開發者ID:RayeWang，項目名稱:easyadmin，代碼行數:14，代碼來源:RoleMapper.java

示例5: selectByExample

@SelectProvider(type=AdminUserSqlProvider.class, method="selectByExample")
@Results({
    @Result(column="id", property="id", jdbcType= JdbcType.INTEGER, id=true),
    @Result(column="name", property="name", jdbcType= JdbcType.VARCHAR),
    @Result(column="psw", property="psw", jdbcType= JdbcType.VARCHAR),
    @Result(column="email", property="email", jdbcType= JdbcType.VARCHAR),
    @Result(column="update_time", property="updateTime", jdbcType= JdbcType.TIMESTAMP),
    @Result(column="update_user", property="updateUser", jdbcType= JdbcType.INTEGER),
    @Result(column="creator", property="creator", jdbcType= JdbcType.INTEGER),
    @Result(column="flag", property="flag", jdbcType= JdbcType.INTEGER),
    @Result(column="last_login_time", property="lastLoginTime", jdbcType= JdbcType.TIMESTAMP)
})
List<AdminUser> selectByExample(AdminUserCriteria example);
開發者ID:RayeWang，項目名稱:easyadmin，代碼行數:13，代碼來源:AdminUserMapper.java

示例6: selectByExample

@SelectProvider(type=UserRoleSqlProvider.class, method="selectByExample")
@Results({
    @Result(column="userid", property="userid", jdbcType= JdbcType.INTEGER, id=true),
    @Result(column="roleid", property="roleid", jdbcType= JdbcType.INTEGER, id=true),
    @Result(column="creator", property="creator", jdbcType= JdbcType.INTEGER),
    @Result(column="create_time", property="createTime", jdbcType= JdbcType.TIMESTAMP)
})
List<UserRole> selectByExample(UserRoleCriteria example);
開發者ID:RayeWang，項目名稱:easyadmin，代碼行數:8，代碼來源:UserRoleMapper.java

示例7: JOIN

@Select({"SELECT r.id, r.name, r.create_time, r.creator, r.description,u.name creatorUser,u1.userid ",
    "FROM role r LEFT JOIN admin_user u ON r.creator=u.id",
    " LEFT JOIN (SELECT roleid,userid FROM user_role WHERE userid=#{userId}) u1 ON r.id=u1.roleid  "})
@Results({
        @Result(column="id", property="id", jdbcType= JdbcType.INTEGER, id=true),
        @Result(column="name", property="name", jdbcType= JdbcType.VARCHAR),
        @Result(column="create_time", property="createTime", jdbcType= JdbcType.TIMESTAMP),
        @Result(column="creator", property="creator", jdbcType= JdbcType.INTEGER),
        @Result(column="description", property="description", jdbcType= JdbcType.VARCHAR),
        @Result(column = "creatorUser",property = "creatorUser",jdbcType = JdbcType.INTEGER)
})
List<Role> selectByUserId(int userId);
開發者ID:RayeWang，項目名稱:easyadmin，代碼行數:12，代碼來源:UserRoleMapper.java

示例8: selectByPrimaryKey

@Select({
    "select",
    "userid, roleid, creator, create_time",
    "from user_role",
    "where userid = #{userid,jdbcType=INTEGER}",
      "and roleid = #{roleid,jdbcType=INTEGER}"
})
@Results({
    @Result(column="userid", property="userid", jdbcType= JdbcType.INTEGER, id=true),
    @Result(column="roleid", property="roleid", jdbcType= JdbcType.INTEGER, id=true),
    @Result(column="creator", property="creator", jdbcType= JdbcType.INTEGER),
    @Result(column="create_time", property="createTime", jdbcType= JdbcType.TIMESTAMP)
})
UserRole selectByPrimaryKey(@Param("userid") Integer userid, @Param("roleid") Integer roleid);
開發者ID:RayeWang，項目名稱:easyadmin，代碼行數:14，代碼來源:UserRoleMapper.java

示例9: selectByExample

@SelectProvider(type=RoleMenuSqlProvider.class, method="selectByExample")
@Results({
    @Result(column="menuid", property="menuid", jdbcType= JdbcType.INTEGER, id=true),
    @Result(column="roleid", property="roleid", jdbcType= JdbcType.INTEGER, id=true),
    @Result(column="flag", property="flag", jdbcType= JdbcType.INTEGER),
    @Result(column="creator", property="creator", jdbcType= JdbcType.INTEGER),
    @Result(column="create_time", property="createTime", jdbcType= JdbcType.TIMESTAMP)
})
List<RoleMenu> selectByExample(RoleMenuCriteria example);
開發者ID:RayeWang，項目名稱:easyadmin，代碼行數:9，代碼來源:RoleMenuMapper.java

示例10: selectByPrimaryKey

@Select({
    "select",
    "menuid, roleid, flag, creator, create_time",
    "from role_menu",
    "where menuid = #{menuid,jdbcType=INTEGER}",
      "and roleid = #{roleid,jdbcType=INTEGER}"
})
@Results({
    @Result(column="menuid", property="menuid", jdbcType= JdbcType.INTEGER, id=true),
    @Result(column="roleid", property="roleid", jdbcType= JdbcType.INTEGER, id=true),
    @Result(column="flag", property="flag", jdbcType= JdbcType.INTEGER),
    @Result(column="creator", property="creator", jdbcType= JdbcType.INTEGER),
    @Result(column="create_time", property="createTime", jdbcType= JdbcType.TIMESTAMP)
})
RoleMenu selectByPrimaryKey(@Param("menuid") Integer menuid, @Param("roleid") Integer roleid);
開發者ID:RayeWang，項目名稱:easyadmin，代碼行數:15，代碼來源:RoleMenuMapper.java

示例11: selectByPrimaryKey

@Select(value = "select id, username, password, nick_name, sex, register_date from user where id = #{id,jdbcType=INTEGER}")
@Results(value = { @Result(column = "nick_name", property = "nickName", jdbcType = JdbcType.VARCHAR), @Result(column = "register_date", property = "registerDate", jdbcType = JdbcType.TIMESTAMP) })
User selectByPrimaryKey(Integer id);
開發者ID:wooui，項目名稱:springboot-training，代碼行數:3，代碼來源:UserMapper.java


注：本文中的org.apache.ibatis.type.JdbcType.TIMESTAMP屬性示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台，相關代碼片段篩選自各路編程大神貢獻的開源項目，源碼版權歸原作者所有，傳播和使用請參考對應項目的License；未經允許，請勿轉載。