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TypeScript O.of方法代码示例

本文整理汇总了TypeScript中b-o-a.O.of方法的典型用法代码示例。如果您正苦于以下问题:TypeScript O.of方法的具体用法?TypeScript O.of怎么用?TypeScript O.of使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在b-o-a.O的用法示例。


在下文中一共展示了O.of方法的7个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的TypeScript代码示例。

示例1: updater

const prop: PropHandler<Counter> = (
  action$: O<A<any>>,
  state: Counter
): O<Counter> => {
  return O.of<Counter>(state).merge<(state: Counter) => Counter>(
    increment$(action$).map(counter => () => counter)
  ).scan((state: Counter, updater: (state: Counter) => Counter) => {
    return updater(state);
  });
};
开发者ID:boajs,项目名称:counter-boa,代码行数:10,代码来源:counter.ts

示例2: property

export default function property(
  state: string,
  action$: O<A<any>>
): O<string> {
  return O
    .of(state)
    .merge(route$(action$).map(({ route: { name } }) => () => name))
    .scan((state: string, updater: Updater<string>) => {
      return updater(state);
    });
};
开发者ID:bouzuya,项目名称:rally-rxjs,代码行数:11,代码来源:current-page.ts

示例3: property

export default function property(
  state: Token,
  action$: O<A<any>>
): O<Token> {
  return O
    .of(state)
    .merge(reset$(action$).map(token => () => token))
    .scan((state: Token, updater: Updater<Token>) => {
      return updater(state);
    });
};
开发者ID:bouzuya,项目名称:rally-rxjs,代码行数:11,代码来源:token.ts

示例4: property

export default function property(
  state: StampRally,
  action$: O<A<any>>
): O<StampRally> {
  return O
    .of(state)
    .merge(reset$(action$).map(stampRally => () => stampRally))
    .scan((state: StampRally, updater: Updater<StampRally>) => {
      return updater(state);
    });
};
开发者ID:bouzuya,项目名称:rally-rxjs,代码行数:11,代码来源:stamp-rally.ts

示例5: property

export default function property(
  state: Spot[],
  action$: O<A<any>>
): O<Spot[]> {
  return O
    .of(state)
    .merge(reset$(action$).map(spots => () => spots))
    .scan((state: Spot[], updater: Updater<Spot[]>) => {
      return updater(state);
    });
};
开发者ID:bouzuya,项目名称:rally-rxjs,代码行数:11,代码来源:spots.ts

示例6: property

export default function property(
  state: SpotForm,
  action$: O<A<any>>
): O<SpotForm> {
  return O
    .of(state)
    .merge(
    changeName$(action$)
      .map(({ value }) => (state: SpotForm) => {
        return Object.assign({}, state, { name: value });
      })
    )
    .scan((state: SpotForm, updater: Updater<SpotForm>) => {
      return updater(state);
    });
};
开发者ID:bouzuya,项目名称:rally-rxjs,代码行数:16,代码来源:spot-form.ts

示例7: property

export default function property(
  state: SignIn,
  action$: O<A<any>>
): O<SignIn> {
  return O
    .of(state)
    .merge(
      changeEmail$(action$)
        .map(({ value }) => (state: SignIn): SignIn => {
          return Object.assign({}, state, { email: value });
        }),
      changePassword$(action$)
        .map(({ value }) => (state: SignIn): SignIn => {
          return Object.assign({}, state, { password: value });
        }),
      reset$(action$)
        .map(() => (state: SignIn): SignIn => {
          return { email: null, password: null };
        })
    )
    .scan((state: SignIn, updater: Updater<SignIn>) => {
      return updater(state);
    });
};
开发者ID:bouzuya,项目名称:rally-rxjs,代码行数:24,代码来源:sign-in.ts


注:本文中的b-o-a.O.of方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。