本文整理汇总了Python中vector.Vector.perp方法的典型用法代码示例。如果您正苦于以下问题：Python Vector.perp方法的具体用法？Python Vector.perp怎么用？Python Vector.perp使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类vector.Vector的用法示例。
在下文中一共展示了Vector.perp方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: point_on_line
# 需要导入模块: from vector import Vector [as 别名]
# 或者: from vector.Vector import perp [as 别名]
def point_on_line(point, line):
if line.degenerate:
return Collisions.points_nearby(point, line.head, 0)
u = line.head - line.tail
v = point - line.tail
if u == v:
return True
if Vector.perp(u, v) != 0:
return False
try:
k = v.x // u.x
except ZeroDivisionError:
k = v.y // u.y
return k == 0示例2: lines_touching
# 需要导入模块: from vector import Vector [as 别名]
# 或者: from vector.Vector import perp [as 别名]
def lines_touching(first, second):
# Returns true if a degenerate, collinear point is on a line.
def within_bounds(point, line):
start, end = line.points
if start.x == end.x:
if point.x <= start.x and point.x >= end.x:
return True
if point.x >= start.x and point.x <= end.x:
return True
else:
if point.x <= start.x and point.x >= end.x:
return True
if point.x >= start.x and point.x <= end.x:
return True
return False
u = first.direction
v = second.direction
w = first.tail - second.tail
q = first.head - second.tail
denom = float(Vector.perp(u, v))
# Parallel, maybe coincident
if denom == 0:
# Check for coincidence
if Vector.perp(u, w) != 0 or Vector.perp(v, w) != 0:
return False
# Check for degeneracy
elif first.degenerate and second.degenerate:
return first.head == second.head
elif first.degenerate:
return within_bounds(first.head, second)
elif second.degenerate:
return within_bounds(second.head, second)
# Check for segment overlap
else:
try:
s = q.x / v.x
t = w.x / v.x
except ZeroDivisionError:
s = q.y / v.y
t = w.y / v.y
if s > t:
s, t = t, s
if s > 1 or t < 0:
return False
return True
# Skew: maybe intersecting.
else:
s = Vector.perp(v, w) / denom
if s < 0 or s > 1:
return False
t = Vector.perp(u, w) / denom
if t < 0 or t > 1:
return False
return True