本文整理汇总了Java中javax.servlet.http.Part.getContentType方法的典型用法代码示例。如果您正苦于以下问题:Java Part.getContentType方法的具体用法?Java Part.getContentType怎么用?Java Part.getContentType使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类javax.servlet.http.Part
的用法示例。
在下文中一共展示了Part.getContentType方法的4个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: fileBoundaryInfo_nullSubmittedFileName
import javax.servlet.http.Part; //导入方法依赖的package包/类
@Test
public void fileBoundaryInfo_nullSubmittedFileName(@Mocked Part part) {
new Expectations() {
{
part.getSubmittedFileName();
result = null;
part.getContentType();
result = "abc";
}
};
RestClientRequestImpl restClientRequest = new RestClientRequestImpl(request, null, null);
Buffer buffer = restClientRequest.fileBoundaryInfo("boundary", "name", part);
Assert.assertEquals("\r\n" +
"--boundary\r\n" +
"Content-Disposition: form-data; name=\"name\"; filename=\"null\"\r\n" +
"Content-Type: abc\r\n" +
"Content-Transfer-Encoding: binary\r\n" +
"\r\n", buffer.toString());
}
示例2: fileBoundaryInfo_validSubmittedFileName
import javax.servlet.http.Part; //导入方法依赖的package包/类
@Test
public void fileBoundaryInfo_validSubmittedFileName(@Mocked Part part) {
new Expectations() {
{
part.getSubmittedFileName();
result = "a.txt";
part.getContentType();
result = MediaType.TEXT_PLAIN;
}
};
RestClientRequestImpl restClientRequest = new RestClientRequestImpl(request, null, null);
Buffer buffer = restClientRequest.fileBoundaryInfo("boundary", "name", part);
Assert.assertEquals("\r\n" +
"--boundary\r\n" +
"Content-Disposition: form-data; name=\"name\"; filename=\"a.txt\"\r\n" +
"Content-Type: text/plain\r\n" +
"Content-Transfer-Encoding: binary\r\n" +
"\r\n", buffer.toString());
}
示例3: getMimeType
import javax.servlet.http.Part; //导入方法依赖的package包/类
public String getMimeType(SectionInfo info)
{
Part file = getMultipartFile(info);
if( file != null )
{
return file.getContentType();
}
return null;
}
示例4: getMultipartContentType
import javax.servlet.http.Part; //导入方法依赖的package包/类
@Override
public String getMultipartContentType(String paramOrFileName) {
try {
Part part = getPart(paramOrFileName);
return (part != null ? part.getContentType() : null);
}
catch (Exception ex) {
throw new MultipartException("Could not access multipart servlet request", ex);
}
}