本文整理汇总了Java中javax.persistence.metamodel.SingularAttribute.isAssociation方法的典型用法代码示例。如果您正苦于以下问题：Java SingularAttribute.isAssociation方法的具体用法？Java SingularAttribute.isAssociation怎么用？Java SingularAttribute.isAssociation使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类javax.persistence.metamodel.SingularAttribute的用法示例。
在下文中一共展示了SingularAttribute.isAssociation方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: containsRelation
import javax.persistence.metamodel.SingularAttribute; //导入方法依赖的package包/类
public static boolean containsRelation(Object expr) {
if (expr instanceof Join) {
return true;
} else if (expr instanceof SingularAttribute) {
SingularAttribute<?, ?> attr = (SingularAttribute<?, ?>) expr;
return attr.isAssociation();
} else if (expr instanceof Path) {
Path<?> attrPath = (Path<?>) expr;
Bindable<?> model = attrPath.getModel();
Path<?> parent = attrPath.getParentPath();
return containsRelation(parent) || containsRelation(model);
} else {
// we may can do better here...
return false;
}
}
示例2: containsRelation
import javax.persistence.metamodel.SingularAttribute; //导入方法依赖的package包/类
public static boolean containsRelation(Object expr) {
if (expr instanceof Join) {
return true;
}
else if (expr instanceof SingularAttribute) {
SingularAttribute<?, ?> attr = (SingularAttribute<?, ?>) expr;
return attr.isAssociation();
}
else if (expr instanceof Path) {
Path<?> attrPath = (Path<?>) expr;
Bindable<?> model = attrPath.getModel();
Path<?> parent = attrPath.getParentPath();
return containsRelation(parent) || containsRelation(model);
}
else {
// we may can do better here...
return false;
}
}