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C# ControllerContext.RenderPartialViewToString方法代码示例

本文整理汇总了C#中System.Web.Mvc.ControllerContext.RenderPartialViewToString方法的典型用法代码示例。如果您正苦于以下问题:C# ControllerContext.RenderPartialViewToString方法的具体用法?C# ControllerContext.RenderPartialViewToString怎么用?C# ControllerContext.RenderPartialViewToString使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在System.Web.Mvc.ControllerContext的用法示例。


在下文中一共展示了ControllerContext.RenderPartialViewToString方法的3个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。

示例1: GetAjaxResponse

        private static AjaxResponse GetAjaxResponse(ControllerContext context, string dataCaptureViewName, object dataCaptureViewModel,
            string contentViewName, object contentViewModel, string viewName, object viewModel, string redirectUrl)
        {
            var response = new AjaxResponse();

            if (!string.IsNullOrEmpty(dataCaptureViewName))
                response.DataCaptureView =  context.RenderPartialViewToString(dataCaptureViewName, dataCaptureViewModel);

            if (!string.IsNullOrEmpty(contentViewName))
                response.ContentView = context.RenderPartialViewToString(contentViewName, contentViewModel);

            if (!string.IsNullOrEmpty(viewName))
                response.Result = context.RenderPartialViewToString(viewName, viewModel);

            if (!string.IsNullOrEmpty(redirectUrl))
                response.RedirectUrl = redirectUrl;
            
            return response;
        }
开发者ID:avijassra,项目名称:CodeLab,代码行数:19,代码来源:JsonResponseActionResult.cs

示例2: GetAjaxResponse

        private static AjaxResponse GetAjaxResponse(ControllerContext context, string popupViewName, object popupViewModel, string contentViewName, object contentViewModel, 
            string resultViewName, object resultViewModel, string redirectUrl)
        {
            var response = new AjaxResponse();

            if (!string.IsNullOrEmpty(popupViewName))
                response.PopupView = context.RenderPartialViewToString(popupViewName, popupViewModel);

            if (!string.IsNullOrEmpty(contentViewName))
                response.ContentView = context.RenderPartialViewToString(contentViewName, contentViewModel);

            if (!string.IsNullOrEmpty(resultViewName))
                response.Result = context.RenderPartialViewToString(resultViewName, resultViewModel);
            else if(resultViewModel != null)
            {
                response.Result = JsonConvert.SerializeObject(resultViewModel); ;
            }

            if (!string.IsNullOrEmpty(redirectUrl))
                response.RedirectUrl = redirectUrl;

            return response;
        }
开发者ID:SadiqAhmed,项目名称:MyNotes,代码行数:23,代码来源:JsonResponseActionResult.cs

示例3: GetAjaxResponse

        private static AjaxResponse GetAjaxResponse(ControllerContext context, string popupViewName, object popupViewModel, string contentViewName, object contentViewModel, 
            string resultViewName, object resultViewModel, string redirectUrl, bool hasError, string message)
        {
            var response = new AjaxResponse();

            response.HasError = hasError;
            response.Message = message;

            if (!string.IsNullOrEmpty(popupViewName))
                response.PopupView = context.RenderPartialViewToString(popupViewName, popupViewModel);

            if (!string.IsNullOrEmpty(contentViewName))
                response.ContentView = context.RenderPartialViewToString(contentViewName, contentViewModel);

            if (!string.IsNullOrEmpty(resultViewName))
                response.Result = context.RenderPartialViewToString(resultViewName, resultViewModel);
            else if(resultViewModel != null)
                response.Result = resultViewModel;

            if (!string.IsNullOrEmpty(redirectUrl))
                response.RedirectUrl = redirectUrl;

            return response;
        }
开发者ID:avijassra,项目名称:MyNotes,代码行数:24,代码来源:JsonResponseActionResult.cs


注:本文中的System.Web.Mvc.ControllerContext.RenderPartialViewToString方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。