本文整理汇总了C++中Rational::simplify方法的典型用法代码示例。如果您正苦于以下问题：C++ Rational::simplify方法的具体用法？C++ Rational::simplify怎么用？C++ Rational::simplify使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Rational的用法示例。
在下文中一共展示了Rational::simplify方法的4个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: getSimplifiedCopy
Rational getSimplifiedCopy(const Rational& rational)
{
Rational simplified = rational;
simplified.simplify();
return simplified;
}示例2: simplify
void Expression::simplify(){
this->coefficent->simplify();
Number* common = this->expr[1]->getCoefficient();
int count;
int opCount;
for (int j = 0; j < this->expr.size() - 1; j++){
count = 0;
opCount = 0;
Rational* rat = new Rational(common, expr[j]->getCoefficient());
rat->simplify();
if (rat->getDenominator()->getType() == "Integer"){
Integer* den = dynamic_cast<Integer*>(rat->getDenominator());
if (den->getValue() != 1){
break;
}
}
else if (rat->getDenominator()->getType() == "Operator"){
opCount++;
}
else{
count++;
}
if (opCount + count == this->expr.size()){
this->coefficent = common;
for (int j = 0; j < this->expr.size() - 1; j++){
Rational* rat = new Rational(this->expr[j]->getCoefficient(), common);
rat->simplify();
this->expr[j]->setCoefficient(rat);
}
}
}
for (int i = 0; i < this->expr.size(); i++){
if (this->expr[i]->getType() == "Operator"){
Operator* opera = dynamic_cast<Operator*>(this->expr[i]);
if (opera->getOperator() == "-"){
this->expr[i] = new Operator("+");
Multiply mult = Multiply();
this->expr[i + 1] = mult.evaluate(this->expr[i + 1], new Integer(-1));
}
this->expr[i]->simplify();
}
}
}示例3: simplify
void NatE::simplify(){
this->exponent->simplify();
this->coefficient->simplify();
if (this->coefficient->getType() == "Rational"){
Rational* newCo = dynamic_cast<Rational*>(this->coefficient);
if (newCo->getNumerator()->getType() == "NatE"){
NatE* newPi = dynamic_cast<NatE*>(newCo->getNumerator());
Add* add = new Add();
this->exponent = add->evaluate(this->exponent, newPi->getExponent());
newCo->setNumerator(newPi->getCoefficient());
newCo->simplify();
this->coefficient = newCo;
}
else if (newCo->getDenominator()->getType() == "NatE"){
NatE* newPi = dynamic_cast<NatE*>(newCo->getDenominator());
Subtract* sub = new Subtract();
this->exponent = sub->evaluate(this->exponent, newPi->getExponent());
newCo->setDenominator(newPi->getCoefficient());
newCo->simplify();
this->coefficient = newCo;
}
}
}示例4: testSimplify
void testSimplify()
{
Rational r = Rational(2,4);
r.simplify();
cout << "Should be (1,2) and was (" << r.getNumerator() << ", " << r.getDenominator() << ").";
}